Tybee Island Nuclear Incident

Date: February 5, 1958 • Location: Tybee Island, United States

After a mid-air collision with a fighter plane during a practice exercise off Tybee Island, Georgia, a U.S. Air Force bomber jettisoned a Mark 15 nuclear bomb, which was presumed lost.

The Tybee Island mid-air collision was an incident on February 5, 1958, in which the United States Air Force lost a 7,600-pound (3,400 kg) Mark 15 nuclear bomb in the waters of Tybee Island near Savannah, Georgia, United States. During a night practice exercise, an F-86 fighter plane collided with the B-47 bomber carrying the large weapon.